Unilevel+projectile+motion

=Unilevel projectile motion=

The defining factor here is that the projectile must launch and land at the same level. This is a way of saying that x (vertical) will be zero. Gravity (g) will be considered as 10msmedia type="custom" key="890235"

math \tilde{f}(\omega)=\int_{-\infty}^{\infty} f(t) e^{-i\omega t}\,dt math

math $\cos(\theta)$\\ math

math \\v^2=u^2+2ax\\ v^2&=&u^2+2ax\\ \therefore math